What is the rate of a reaction if the value of k is 0.01, (A) is 2 M, and (B) is 3 M?
Rate = K[A]^3[B]^2
A. 0.36 (mol/L)/s
B. 72 (mol/L)/s
C. 1.08 (mol/L)/s
D. 0.72 (mol/L)/s

rate = 0.72 M/s

Explanation:

Given data:

Rate equation = K[A]³[B]²

Concentration of A = 2M

Concentration of B = 3M

K = 0.01

Solution:

Substituting values,

rate = 0.01M⁻⁴s⁻¹ ×[2M]³ ×[3M]²

rate = 0.72 M/s

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