Chemistry, 21.12.2020 01:00 Tamiahufflululu

What do safeguarding devices do to protect the worker? (Select 3)
A) Detects operator contact with the machines point of operation

B) Prevents operator contact with the machines point of operation

C) Stops hazardous action if a workers body part comes to close

D) Acts as a barrier between the worker and the machine.

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Answer from: emmadivaburnsox7ae9

(A) Detects operator contact with the machines point of operation

(D) Acts as a barrier between the worker and the machine.

Explanation:

(A) Detects operator contact with the machines point of operation: This is a necessary point for the Safeguarding device because when it will detect it can make sure that whatever the person is working on, is safe or not. Therefore the safeguarding device should be detecting operator's contact but not interrupting unnecessarily.

(C) Stops hazardous action if a workers body part comes too close: Safeguarding device must protect the worker body part from that comes too close to any harmful or hazardous machines, like a safeguarding device should prevent the operator from going too close to the crusher machine as it can lead to injuries.

(D) Acts as a barrier between the worker and the machine: The safeguarding device should be acting as a barrier between the operator and the machine as it will prevent any injuries to the operator. The device should not be preventing the worker to work but should act a protective shield between the machines and the operator.

Answer from: Quest

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = $25^oc$ = 298 k $)0^oc=273kelvins$

$o_3+3no\rightarrow 3no_2,\delta h_{reaction}=? [/)</p><p>[tex]\delta h_{no}=90.4kj/mol$

$\delta h_{no_2}=33.85kj/mol$

$\delta h_{o_3}=142.2kj/mol$

$\delta h_{reaction}=\sum \delta h_{products}-\sum\delta h_{reactants}=3\times\delta h_{no_2}-(3\times \delta h_{no}+\delta h_{o_3})$

$\delta h_{reaction}=33.85-(90.4+142.2)=-311.85kj/mol$

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

$v_{no}=12.00 l,v_{o_3}=8.50 l$

$pv_{no}=n_{no}rt=1atm \times 12.00 l=n_{no}\times 0.0821 atml/k mol \times 298 k$

$n_{no}=0.49 moles$

$pv_{o_3}=n_{o_3}rt=1atm \times 8.50 l=n_{o_3}\times 0.0821 atml/k mol \times 298 k$

$n_{o_3}=0.34 moles$

according to reaction 3 moles no are reacting with 1 mol of $o_3$ ,then 0.49 mol of no will react with $\frac{1}{3}\times 0.49$ moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and $o_3$ is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

$\delta h_{reaction}\times \text{moles of no}=-311.85kj/mol\times 0.49 mol=-152.80kj/mol$

Answer from: Quest

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.

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What do safeguarding devices do to protect the worker? (Select 3)
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