A photon has a wavelength of approximately 2 x 10-7m. What is the energy, in joules, associated with this photon? A. More information is needed.
B. 4x 10-32
C. 1.5 x 1015
D. 1x 10-18
E. 1x 1018 SUBMIT

E = 9.95×10⁻¹⁹ J

Explanation:

Given data:

Wavelength = 2×10⁻⁷ m

Energy of photon = ?

Solution:

Formula:

E = hc/λ

h = 6.63×10⁻³⁴ Js

c = 3×10⁸ m/s

by putting values,

E =  6.63×10⁻³⁴ Js × 3×10⁸ m/s / 2×10⁻⁷ m

E = 19.89×10⁻²⁶Jm / 2×10⁻⁷ m

E = 9.95×10⁻¹⁹ J

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j