Given the balanced equation 2(h2 s) + 3(o2) = 2(s o2) + (h2 o)
what is the correct mole ratio set?
h2 s: s o2 = 2: 2 , o2: h2 o
2: 2, 3: 2
2: 3, 3: 2
4: 4, 5: 4
4: 6, 4: 4

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%