If 43.7 g of iron is completely used to produce 62.5 g of iron (III) oxide, how many grams of oxygen are involved in the reaction?

Mass of Oxygen : 18.8 g

Reaction(balanced) :

4Fe + 3O₂ → 2Fe₂O₃

mass Fe = 43.7 g

mol Fe(MW= 55,845 g/mol) :

mol O₂ : mol Fe = 3 : 4, so mol O₂ :

Mass O₂(MW=32 g/mol) :

Or simply you can Conservation of mass, where the masses before and after the reaction are the same

mass reactants=mass products

mass iron+mass oxygen=mass  iron (III) oxide

43.7 g + mass oxygen=62.5 g

mass oxygen = 62.5 - 43.7 = 18.8 g

answer: i dont know the answer but this might

explanation:

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