If an excess of nitrogen is reacted with 3.41 grams of hydrogen how many grams of ammonia can be produced?

Molar mass:

H2 = 2 g/mol
NH3 = 17 g/mol

Mole ratio:

3 H2 + N2 = 2 NH3

3 x 2 g H2 2 x 17 g NH3
3.41 g H2 ??

3.41 x 2 x 17 / 3 x 2 =

115.94 / 6 => 19.32 g of NH3