A 25.00 mL sample of vinegar was titrated with 39.27 mL of 0.4293 M NaOH. Calculate the concentration of acetic acid in the vinegar sample. HC2H302 + NaOH NaC2H302 + H2O

0.6743 M

Explanation:

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

First we calculate how many NaOH moles reacted, using the definition of molarity:

One NaOH moles reacts with one acetic acid mole, so the vinegar sample contains 16.86 mmoles of acetic acid as well.

Finally we calculate the concentration (molarity) of acetic acid:

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