1. How much heat is required to heat 22 grams of Aluminum from 15 °C to 49° C

670.956

Explanation:

You can use this equation to solve for heat :

Q = m * c * ΔT

Q represents the heat

m represents the mass in kilograms

c is the specific heat. For aluminum, it's 897

ΔT is the change in temperature, so, 49 - 15 which is 34

Plug in the numbers and you get this :

Q = 0.022 * 897 * 34

Q = 670.956 Joules

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.