(03.06 HC) The boiling point of bromine is 59 °C. Which of the following best predicts the boiling point of iodine monochloride, a polar compound?

Group of answer choices

Lower than 59 °C because ionic bonding in bromine is stronger than covalent bonding in iodine monochloride.

Lower than 59 °C because dipole-dipole interactions in iodine monochloride are weaker than in bromine.

Higher than 59 °C because dipole-dipole interactions in iodine monochloride are stronger than dispersion forces in bromine.

Higher than 59 °C because ionic bonding in iodine monochloride is stronger than H-bonding in bromine.

Ok where is the image ?

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.