The reaction between lead(II) nitrate and aluminum chloride produces lead(II) chloride and aluminum nitrate. Find the mole ratios of lead(II) nitrate to aluminum chloride and lead(ll)
chloride to aluminum nitrate.

A. 3:2 and 3:2
B. 3:3 and 2:2
C. 3:2 and 2:3
D. None of the above

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o

answermeridional ;