How many phosphorus atoms are in two moles of the compound Mg3(PO4)2? O 4 atoms O 1.2 x 1023 O 2 atoms O 2.4 x 1023

The number of phosphorus atoms : 2.408 x 10²⁴

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

moles of Mg₃(PO₄)₂ = 2

moles of phosphorous(P) atoms in Mg₃(PO₄)₂ ⇒ mol ratio of elements in the compound(for P=2)

The number of atoms of  phosphorous(P) :

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.