When heated, kclo3 decomposes into kcl and o2. kclo3--> 2kcl+ 3o . if this reaction produced 62.6 g of kcl, how much o2 was produced (in grams)?

The solution to your problem is as follows:

 2 KClO3 → 2 KCl + 3 O2 

MW of KCL = 39.1 + 35.35 = 74.6 g/mole 

62.6/74.6 = 0.839 moles KCl produced 

0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced

Therefore, there are 40.27g of O2 produced during the reaction.

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