A serving of Cheez-Its releases 130 kcal (1 kcal = 4.18 kJ) when digested by your body. If this same amount of energy were transferred to 2.5 kg of water at 27˚C, what would the final temperature be?

The final temperature : 78.925°C

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Energy releases = 130 kcal = 130 x 4.18 kJ=543.4 kJ

The final temperature :

Final temperature :

ΔT=final-initial

51.925°c=final-27°c

final = 51.925+27=78.925°C

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