Answers: 3
![\tt [OH^-]=2\times 2.10^{-2}=4.10^{-2}~M](/tpl/images/0978/2687/03c7a.png)
![\tt pOH=-log[OH^-]\\\\pOH=-log~4.10^{-2}\\\\pOH=2-log~4\rightarrow 1.398 \\\\pH+pOH=14\\\\pH=14-1.398\\\\pH=12.6](/tpl/images/0978/2687/ddbd2.png)
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