At 273°K and 1 atm (STP), the volume of a gas is 1000ml. If the temperature changes to 298° K and the pressure is doubled, what is the new volume of the gas?

V₂ = 545.79 mL

Explanation:

Given data:

Initial volume = 1000 mL

Initial pressure = 1 atm

Initial temperature = 273 K

Final temperature = 298 K

Final volume = ?

Final pressure = 2 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm × 1000 mL × 298 K / 273 K × 2 atm

V₂ = 298000 atm .mL. K / 546 K.atm

V₂ = 545.79 mL

if you're asking what comes out, it's steam.