Consider the following reaction where Kc = 1.29x10-2 at 600 K. 9
CoCl2(g) =CO(g) + Cl2(g)
q
A reaction mixture was found to contain 0.104 moles of CoCl2(g), 4.34x10-2 moles of CO(g), and 3.95x10-2 moles of
Cl2(g), in a 1.00 liter container.
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Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?
The reaction quotient, Qo, equals
The reaction
A. must run in the forward direction to reach equilibrium.
B. must run in the reverse direction to reach equilibrium.
C. is at equilibrium.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

4d^55s^1 ( third choice)

sup bro, im dumb, but this is what i found xd

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