A sample of gas has a volume of 400 liters when its temperature is 20.C and its pressure is 300.mm of Hg. What volume will the gas occupy at STP?

V₂ = 145.35 L

Explanation:

Given data:

Initial volume = 400 L

Initial pressure = 300 mmHg (300/760 =0.39 atm)

Initial temperature = 20 °C (20 +273 = 293 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂  /T₁ P₂

V₂ =  0.39 atm × 400 L × 273 K / 293 K × 1 atm

V₂ = 42588 atm.L.K /293 K.atm

V₂ = 145.35 L

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it