If 25.0 mL of 0.100 M Ca(OH)2 is titrated with 0.200 M HNO3, what volume of nitric acid is required to neutralize the base?

25 mL

Explanation:

The reaction that takes place is:

First we calculate how many Ca(OH)₂ moles were spent in the titration:

Then we convert Ca(OH)₂ moles into HNO₃ moles, using the stoichiometric ratio:

Finally we calculate the volume of required nitric acid solution, using the concentration:

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