Arrange the aqueous solutions from the most acidic to the most basic, at 25 C. Acidic
[OH | = 1x 10^-7 M
[OHT|=1× 10^-9 M
[H"] = 1 x 10^-3 M
pH = 11

The given aqueous solutions begin from the most acidic to the most basic at a given temperature of 25°C would be:

pH 3 > pH 5 > pH 7 > pH 11

x

so,

× x

x

x }

∵ pH = 7

Similarly, the others we get as:

pH = 5

pH = 3

and pH = 11

As we know the lower the rank, the more acidic the solution is.

Thus, the correct arrangement from acidic to basic would be pH 3 > pH 5 > pH 7 > pH 11

Learn more about "Solution" here:

link

See explanation below

Explanation:

If [OH | = 1x 10^-7 M then [H^+] = 1 * 10^-14/1x 10^-7 = 1x 10^-7 M

pH = - log [H^+]  = -log [1x 10^-7]

pH = 7

If [OH | = 1x 10^-9 M then [H^+] = 1 * 10^-14/1x 10^-9 = 1x 10^-5 M

pH = - log [H^+]  = -log [1x 10^-5]

pH = 5

[H^+] = 1 x 10^-3 M

pH = - log [H^+]  = -log [1x 10^-3]

pH = 3

Hence the decreasing acidity;

pH 3 > pH 5 > pH 7 > pH 11

The most acidic is pH 3 while the most basic is pH 11

um i think it might be a car?