Which equation shows how to calculate how many grams (g) of KCl would be produced from 4 mol KOH? The balanced reaction is:
MgCl2 + 2KOH → Mg(OH)2 + 2KCI
A.
4 mol KOH
1
X
1 mol KCI
2 mol KOH
х
74.55 g KCI
1 mol KCI
4 mol KOH
OB.
1 mol KOH
1 mol KCI
х
74.55 g KCI
1 mol KCI
O c.
4 mol KOH
1
2 mol KCI
х
1 mol KOH
х
74.55 g KCI
1 mol KCI
O D.
4 mol KOH 2 mol KCI
х
1
2 mol KOH
74.55 g KCI
1 mol KCI

here's the link to your question!

explanation:

your answer would be “dry”

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.