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Empirical formula is C₅H₁₂O

Molecular formula = C₅H₁₂O

Explanation:

Given data:

Percentage of hydrogen =13.75%

Percentage of carbon = 68.11%

Percentage of oxygen = 18.15%

Empirical formula = ?

Solution:

Number of gram atoms of H = 13.75 / 1.01 = 13.6

Number of gram atoms of O = 18.15 / 16 = 1.13

Number of gram atoms of C = 68.11 / 12 = 5.68

Atomic ratio:

            C                      :      H               :         O

           5.68/1.13           :     13.6/1.13     :       1.13/1.13

            5                      :        12          :        1

C : H : O = 5 : 12 : 1

Empirical formula is C₅H₁₂O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass :

5×12 + 12×1.01 + 16×1 = 88.12 g/mol

n = 88.17/ 88.12

n = 1

Molecular formula = n (empirical formula)

Molecular formula = 1 (C₅H₁₂O)

Molecular formula = C₅H₁₂O