Calculate the actual mass of one atom of carbon if 12g of cardron contains one mole of carbon.

2.0 × 10⁻²³ g C

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

1 atom C

Step 2: Identify Conversions

Avogadro Number

Molar Mass of C - 12.01 g/mol

Step 3: Convert

= 1.99435 × 10⁻²³ g C

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

1.99435 × 10⁻²³ g C ≈ 2.0 × 10⁻²³ g C

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

explanation:

0.07 g/cm³

1.37 g/cm³