¿Cuántos gramos de nitrato de magnesio Mg(NO3)2 se pueden obtener a partir de 5g de magnesio Mg? Considere la siguiente reacción: Mg + 4 HNO3⟶Mg(NO3)2 + 2 H2O + N2 + 2 O2

30 g

Explanation:

Paso 1: Escribir la reacción balanceada

Mg + 4 HNO₃ ⟶ Mg(NO₃)₂ + 2 H₂O + N₂ + 2 O₂

Paso 2: Convertir 5 g de Mg a moles

La masa molar de Mg es 24,31 g/mol.

5 g × 1 mol/24,31 g = 0,2 mol

Paso 3: Calcular los moles de Mg(NO₃)₂ generados a partir de 0,2 moles de Mg

La relación molar de Mg a Mg(NO₃)₂ es 1:1. Los moles de Mg(NO₃)₂ generados son 1/1 × 0,2 mol = 0,2 mol.

Paso 4: Calcular la masa correspondiente a 0,2 moles de Mg(NO₃)₂

La masa molar de Mg(NO₃)₂ es 148,3 g/mol

0,2 mol × 148,3 g/mol = 30 g

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