How many molecules of glucose (C6H12O6,M=180.18g/mol) are contained in 144mL of 0.280 M glucose solution?

Volume of Glucose solution = 144 mL  OR 0.144 L

Molarity of Glucose solution = 0.280 M

From the definition of Molarity, we know that:

Molarity = number of moles / volume(in L)

in this equation, multiplying both sides by Volume, we get:

number of moles = Molarity*Volume(in L)

replacing the variables

Number of moles = 0.280*(0.144L)

Number of moles = 0.04

We know that:

Number of molecules = Number of Moles * Avogadro's number

Number of molecules = 0.04 * 6.022 * 10²³

Number of molecules = 0.24088 * 10²³

Number of molecules = 2.4088 * 10²²

Therefore, there are 2.4088 * 10²² molecules of Glucose in the given solution

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

the dissolution of polymer can be thermodynamically described in 2 steps.