Explain how the rate of diffusion of a gas is related to its molar mass. Carbon dioxide gas (CO2) effuses 3.2 times faster than an unknown gas. Determine the molar mass of the unknown gas

450.24

Explanation:

According to Graham's law of diffusion:

R1/R2 = √M.M2 / √ M.M1

where

R1 = rate if diffusion of the first gas

R2 = rate of diffusion of the second gas

M.M2 = molar mass of the second gas

M.M1 = molar mass of the first gas

The first gas is CO2 and CO2 has a molar mass of 44

R1/R2 = 3.2

Substitute all the values into the equation:

3.2 = √M.M2 / √44

Squaring both sides:

3.2^2 = M.M2 / 44

Cross multiply as follows:

M.M2 = 3.2*3.2*44

= 450.56

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b is the correct answer

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