What mass of calcium chloride is required to prepare 3.20 L of 0.850 M of calcium chloride solution?

301.92 g of CaCl2.

Explanation:

The following data were obtained from the question:

Volume of CaCl2 solution = 3.20 L

Molarity of CaCl2 solution = 0.850 M

Mass of CaCl2 =?

Next, we shall determine the number of mole of CaCl2 in the solution. This can be obtained as illustrated below:

Volume of CaCl2 solution = 3.20 L

Molarity of CaCl2 solution = 0.850 M

Mole of CaCl2 =?

Molarity = mole /Volume

0.850 = mole of CaCl2 /3.20

Cross multiply

Mole of CaCl2 = 0.850 × 3.20

Mole of CaCl2 = 2.72 moles

Finally, we shall determine the mass of the CaCl2 needed to prepare the solution as follow:

Mole of CaCl2 = 2.72 moles

Molar mass of CaCl2 = 40 + (2×35.5)

=40 + 71

= 111 g/mol

Mass of CaCl2 =?

Mole = mass /Molar mass

2.72 = mass of CaCl2 /111

Cross multiply

Mass of CaCl2 = 2.72 × 111

Mass of CaCl2 = 301.92 g

Therefore, 301.92 g of CaCl2 is needed to prepare the solution.

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current