What is the percent yield of titanium (IV) oxide, if 10.2 g are formed when 25.7 g of titanium (IV) chloride react?
TiCl4 (s) + O2 (g) - TiO2 (s) + 2 Cl2 (g)

Percent yield = 91%

Explanation:

Given data:

Percent yield of TiO₂ = ?

Actual yield = 10.2 g

Mass of TiCl₄ react = 25.7 g

Solution:

Chemical equation:

TiCl₄  + O₂   →    TiO₂  + 2Cl₂

Number of moles of TiCl₄:

Number of moles = mass/molar mass

Number of moles = 25.7 g/ 189.7 g/mol

Number of moles = 0.14 mol

Now we will compare the moles of  TiCl₄  and TiO₂.

                       TiCl₄           :            TiO₂

                         1                :              1

                         0.14           :              0.14

Theoretical yield:

Mass = number of moles ×molar mass

Mass = 0.14 mol × 79.86 g/mol

Mass = 11.2 g

Percent yield:

Percent yield = [actual yield / theoretical yield ]  × 100

Percent yield = [10.2 g / 11.2 g ]× 100

Percent yield = 91%

the answer to your question is c