_AgF + _CaCl2 --> _ AgCl + _ CaF2 3 AgF + 8 CaCl2 -->16 AgCl + 7 CaFz
4 AgF+ 3 CaCl2 --> 2 AgCl + 1 CaF2
1 AgF+ 1 CaCl2 -->1 AgCl + 1 CaF2
✓
2 AgF + 1 CaCl2 --> 2 AgCI + 1 CaF2

it is b that is the answer.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o

the correct answer is c