A 100.0 mL solution of 0.0200 M Fe3+ in 1 M HClO4 is titrated with 0.100 M Cu+, resulting in the formation of Fe2+ and Cu2+. A Pt indicator electrode and a saturated Agā£ā£AgCl electrode are used to monitor the titration.
Calculate the values of for the cell after each of the given volumes of the Cu+Cu+ titrant have been added.
10.0 ml E = ? V
19.5 ml E = ? V
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A 100.0 mL solution of 0.0200 M Fe3+ in 1 M HClO4 is titrated with 0.100 M Cu+, resulting in the for...
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