A 30.00 mL sample of vinegar is titrated with 0.4190 M NaOH(aq). If the titration requires 27.83 mL of NaOH(aq), what is the concentration of acetic acid in the vinegar?

0.389 M

Explanation:

Using the formula; CaVa = CbVb

Where;

Ca = concentration of acid

Cb = concentration of base

Va = volume of acid

Vb = volume of base

Based on the provided information in the question, Va = 30mL, Ca=?, Vb = 27.83mL, Cb = 0.4190 M

Hence, CaVa = CbVb

Ca = CbVb/Va

Ca = 0.4190 × 27.83 ÷ 30

Ca = 11.6607 ÷ 30

Ca = 0.3886

Ca = 0.389 M

Therefore, the concentration of acetic acid in the vinegar is 0.389 M

answer; /// i do believe that the correct answer is (a) boiling