#45 State whether the following sets of quantum numbers are valid. If the set of quantum numbers aren’t valid, indicate why. Indicate what orbital the electron is in regardless of whether the numbers are valid or not. n = 3 l = 3 ml= 0 ms= +1/2
n = 2 l = 1 ml= -1 ms= -1/2
n = 3l = 0 ml= 1 ms= +1/2
#46 Give the “COMPLETE” electron configuration for antimony. Is it paramagnetic or diamagnetic? If there are unpaired electrons, indicate how many.

(a) "l" cant be more than n-1.  n= 3 so l cant be more than 2.

(b) Valid

(c) If l=0, ml can only be 0.

Sb, Antimony, 51 electrons

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p3

paramagnetic 3 unpaired electrons

Explanation:

(a) "l" (lower case L) can be 0, 1, 2 up to n-1.  If n=3, l can be 0, 1, or 2.

(b) This set of quantum numbers is valid.  n can be 1, 2, 3, ...

since n= 2, l can be any number from 0 to n-1 or 0,1

Since l=1, ml can be -1, 0, 1

ms can always be +1/2 or -1/2

(c) ml can only be from -l to +l.  If l=0, ml=0.

If l was 2, ml could be -2, -1, 0, 1, 2

you need to have a picture of the atom that way we can answer it

rosa was looking for patterns to predict the products of chemical reactions. she recorded three similar decomposition reactions in the table.she should record 2licl + 3o2.

in the last row of the table. it is the thermal decomposition of chlorate lithium, hence, she should record these products as: lithium chloride ( 2licl ) and oxygen ( 3o2 )   2 > 2 licl + 3o2.