Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced reaction is:
MgCl2 + 2KOH → Mg(OH)2 + 2KCI

A.

General Formulas and Concepts:

Chemistry - Stoichiometry

Explanation:

Step 1: Define

Given:   4 mol Mg(OH)₂

RxN:   MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl

Step 2: Identify Conversions

Molar Mass of K - 39.10 g/mol

Molar mass of O - 16.00 g/mol

Molar mass of H - 1.01 g/mol

Molar Mass of KOH - 39.10 + 16.00 + 1.01 = 56.11 g/mol

Step 3: Stoichiometry

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

it would be a gas formation