Now consider a sample of the gas at 33 deg C, 744 mm Hg, and 450 mL. If the pressure is decreased to 725 mm Hg and the temperature raised to 66C. What is the new volume of the gas? New volume =

V₂ =  511.59mL

Explanation:

Given data:

Initial volume = 450 mL

Initial pressure = 744 mmHg

Initial temperature = 33°C (33 +273 = 306 K)

Final temperature = 66°C (66+273 = 339 K)

Final pressure = 725 mmHg

Final volume =?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 744 mmHg × 450 mL × 339 K / 306 K ×725 mmHg

V₂ = 113497200 mmHg .mL. K / 221850 K.mmHg

V₂ =  511.59mL

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