A system absorbs 191 kJkJ of heat and the surroundings do 120 kJkJ of work on the system. Part A What is the change in internal energy of the system?

the change in internal energy of the system is 311 kJ

Explanation:

Given that;

A system absorbs a heat dQ = 191 kJ

And the the surroundings do work on the system dW = 120 kJ

change in internal energy of the system = ?

We take a look at the first law of thermodynamic

Initially the system absorbs energy ( dQ =1 91 kJ) as heat.

Then the surroundings do work (dW = 120kJ) on the system,

Hence the system gains 120 kJ more.

The total energy change is = heat + work

dU = dQ + dW

dU = 191 + 120

dU = 307 kJ

change in internal energy = 311 kJ

Therefore the change in internal energy of the system is 311 kJ

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

its first and third is your answer i did the qustion the fourth isnt right