A sheet of aluminum measures 55.0 cm by 23.3 cm. If the volume is 2.90 cm^3 what is the thickness of the foil? Express your answer with the appropriate units.

0.0023 cm

Explanation:

The following data were obtained from the question:

Length (L) = 55 cm

Breadth (B) = 23.3 cm

Volume (V) = 2.9 cm³

Thickness (T) =?

Thus, we can obtain the thickness of the aluminum foil as illustrated below:

V = L × B × T

2.9 = 55 × 23.3 × T

2.9 = 1281.5 × T

Divide both side by 1281.5

T = 2.9/1281.5

T = 0.0023 cm

Therefore, the thickness of the aluminum foil is 0.0023 cm