Making the simplistic assumption that the dissolved nacl(s) does not affect the volume
of the solvent water, determine the constants m and b in the equation molarity = m⋅density + b that relates the nacl molarity to the nacl(aq) density. take the density of water to be 1.00 g/ml and the molar mass of nacl to be 58.5 g/mol.

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if we assume volume NaCl + volume H2O = volume H2O.. i.e.. NaCl does not effect volume 

therefore.. the units of.. 
.. M = moles NaCl / L solution ≈ moles NaCl / L H2O 
.. density = grams NaCl / L solution ≈ grams NaCl / L H2O 
again.. that is our assumption 

so we can readily see that 
.. M = (1 mol NaCl / ___g NaCl) x (__g NaCl / L H2O) + 0 
ie.. 
.. M = (1 mol NaCl / 58.5g NaCl) x density solution + 0 

so.. we would expect.. 
.. m = 0.01709 mol / g 
.. b = 0 

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !