A balloon contains 146.0mL of gas confined at a pressure of 1.30atm and a temperature of 5.00ºC. If the pressure changes to 2.60 atm and the temperature decreases to 2.00ºC, what will be the volume of gas in the balloon?

V₂ = 72.2 mL

Explanation:

Given data:

Initial volume = 146.0 mL

Initial pressure = 1.30 atm

Initial temperature = 5.00 °C (5.00 +273 = 278 K)

Final temperature = 2.00  °C ( 2.00+273 = 275 K)

Final volume = ?

Final pressure = 2.60 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂  /T₁P₂

V₂ = 1.30 atm × 146.0 mL × 275 K / 278K × 2.60 atm

V₂ = 52195  atm .mL. K / 722.8 K.atm

V₂ = 72.2 mL

the equation that correctly represent the reaction for formation of ammonia is

n2+ 3h2 → 2nh3 (answer d)

1 mole of nitrogen gas (n2) react with 3 moles of hydrogen gas (h2) to form 2 moles of ammonia ( nh3). this is in a process known as haber process were iron is used as a catalyst and reaction take place that a higher temperature and pressure. the process is exothermic hence energy is released.

i belive it is water