How many grams of aluminium chloride are produced when 123.2g of chlorine react with aluminium

Mass = 154.67 g

Explanation:

Given data:

Mass of aluminum chloride produced = ?

Mass of chlorine = 123.2 g

Solution:

Chemical equation:

2Al + 3Cl₂  →   2AlCl₃

Number of moles of chlorine:

Number of moles = mass/molar mass

Number of moles = 123.2 g/ 71 g/mol

Number of moles =1.74 mol

Now we will compare the moles of aluminum chloride and chlorine.

                          Cl₂              :              AlCl₃

                            3               :                 2

                           1.74            :          2/3×1.74 = 1.16 mol

Mass of AlCl₃:

Mass = number of moles × molar mass

Mass =  1.16 mol × 133.34 g/mol

Mass = 154.67 g

well in order to answer this question you have to provide more information < 3

dynamic equilibrium is the answer.