What pressure is required to compress 200 liters of air at 100 atmosphere into a cylinder whose volume is 20.0 liters?

P₂ = 1000 atm

Explanation:

Given data:

Initial volume of air = 200 L

Initial pressure = 100 atm

Final volume = 20.0 L

Final pressure required = ?

Solution:

The given problem will be solved through the Boly's law,

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

100 atm × 200 L= P₂  × 20.0 L

P₂ = 20,000 atm. L/ 20.0 L

P₂ = 1000 atm

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

answer: c.

explanation: