Determine the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (C6H12O6 ) in 250.0 mL of water. The vapor pressure of pure water at 25°C is 23.8 torr

Explanation:

= Molar mass of glucose = 180.2 g/mol

= Molar mass of water = 18 g/mol

= Mass of glucose = 76.6 g

= Mass of water =

= Vapor pressure of pure water at 25°C = 23.8 torr

The mole fraction of glucose is

Mole fraction of the solute would be

The vapor pressure of the solution is .

answer; i believe that the correct answer is (a) potassium(k)

your answer is c) plasma

~*"auba14"*~