Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachloride would be produced by this reaction if of chlorine were consumed

0.56 mL

Explanation:

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachloride would be produced by this reaction if 1.1 mL of chlorine were consumed.

Step 1: Write the balanced equation

CH₄(g) + 2 Cl₂(g) → CCl₄(g) + 4 HCl (g)

Step 2: Calculate the moles corresponding to 1.1 mL of Cl₂

At standard temperature and pressure, 1 mole of a gas has a volume of 22.4 L.

1.1 × 10⁻³ L × 1 mol/22.4 L = 4.9 × 10⁻⁵ mol

Step 3: Calculate the moles of CCl₄ formed from 4.9 × 10⁻⁵ moles of Cl₂

The molar ratio of Cl₂ to CCl₄ is 2:1. The moles of CCl₄ are 1/2 × 4.9 × 10⁻⁵ mol = 2.5 × 10⁻⁵ mol.

Step 4: Calculate the volume corresponding to 2.5 × 10⁻⁵ moles of CCl₄

At standard temperature and pressure, 1 mole of a gas has a volume of 22.4 L.

2.5 × 10⁻⁵ mol × 22.4 L/mol = 5.6 × 10⁻⁴ L = 0.56 mL

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