EMERGENCY! WILL GIVE 78 POINTS AND BRAINLIEST TO FASTEST CORRECT ANSWER! Write chemical equations for each of the following
decomposition reactions. One or more products might
be identified.
a.) magnesium bromide
b.) cobalt (II) oxide
c.) titanium (IV) hydrogen titanium (IV) oxide + water
d.) barium carbonate -> barium oxide + carbon dioxide

One or more products might be identified. a. ... [math]\text { barium carbonate } \rightarrow \text { barium oxide }+\text { carbon dioxide } ... [math]\begin{array}{l}{\text { titanium (IV) hydroxide - titanium(IV) }} \\ {\text { oxide + water }}\end{array}[/math] d. ... Write chemical equations for each of the following decomposition reactions.

Explanation: there ya go hoped this helps you!

idk what is it? is this a question that you know the answer or u dont

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.