a gas container with a volume of 271 mL contains 0.26 moles of gas. Gas is added to the container so that it now contains 0.80 mole of gas. what is the new volume in milliliters

V₂  = 833.85 mL

Explanation:

Given data:

Initial volume V₁= 271 mL

Initial number of moles n₁= 0.26 mol

Final number of moles n₂= 0.80 mol

Final/new volume V₂ = ?

Solution:

V₁/n₁   =    V₂/n₂

Now we will put the values in formula.

271 mL / 0.26 mol = V₂ / 0.80 mol

V₂  = 271 mL × 0.80 mol / 0.26 mol

V₂  = 216.8 mL.mol /  0.26 mol

V₂  = 833.85 mL

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied