I need a hand with this one: Having this equation:
Na2SO4 +BaCl2 = BaSO4+NaCl
If 10.09 grams of Na2SO4 were added to a 50mL barium solution and reacted completely, what was the BaCl2 molarity of the solution?
Yes, I already know its a displacement reaction

Thx

[BaCl₂] = 1.42M

Explanation:

Given:    Na₂SO₄(aq) + BaCl₂(aq) => 2NaCl(aq) + BaSO₄(s)

The balanced equation shows a 1:1 reaction between Na₂SO₄(aq) & BaCl₂(aq) and means the moles of sodium sulfate used equals the moles of baium chloride used. The concentration is the theoretical mole value calculated divided by 0.050 Liters.

Na₂SO₄(aq) + BaCl₂(aq) => 2NaCl(aq) + BaSO₄(s)

Moles of Na₂SO₄(aq) = moles of BaCl₂(aq) = 10.09g/142.04g/mol = 0.071mole

∴ Molar Concentration of BaCl₂(aq) = moles BaCl₂/Volume of Soln in Liters

= 0.071mole/0.050Liters = 1.42M in BaCl₂.  

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be