What mass of citric acid (molar mass = 192.14g/mol) would be needed to make 0.10 L of 5.00 M citric acid solution ?

Mass = 96.07 g

Explanation:

Given data:

Mass of citric acid = ?

Molar mass of citric acid = 192.14 g/mol

Volume of citric acid solution = 0.10 L

Molarity of solution = 5.00 M

Solution:

First of all we will calculate the number of moles from molarity formula. Then we will determine the mass from moles formula.

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

5.00 M = n/0.10 L

n = 5.00 mol/L× 0.10 L

n =0.5 mol

Mass of citric acid:

Number of moles = mass/molar mass

0.5 mol = mass/ 192.14 g/mol

Mass = 0.5 mol  × 192.14 g/mol

Mass = 96.07 g

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