How many grams of hydrogen are in 6.0g of sucrose?

The formula for sucrose is

C12H22O11

moles sucrose = mass / molar mass  

= 6.0 g / 342.30 g/mol

= 0.017528 mol

the formula shows that each sucrose molecule has 22 H atoms

so moles H = 22 x moles sucrose

= 0.3856 mol

mass H = molar mass x moles

= 1.008 g/mol x 0.3856 mol

= 0.3887 g

= 0.39 g ( 2 sig figs)

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

dynamic equilibrium is the answer.