Depicted below you will see the molecules COH2 and SO3 . Why is COH2 polar while SO3 isn’t?

See explanation

Explanation:

When we look at SO3 we will notice that the compound is trigonal planar and it is symmetric. This means that it has equal charge distribution hence its dipoles cancel out resulting in a zero net dipole moment.

However, COH2 is also trigonal planar but is non-symmetric. Hence, its dipole moments do not cancel out, hence the molecule has a resultant dipole moment and is a polar molecule

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

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