Question 11 What/mass of oxygen is needed to fill a 585 L tank at STP?
0.417 kg
0.835 kg
0.765 kg

0.835 Kg

Explanation:

We'll begin by calculating the number of mole of oxygen that will fill 585 L tank at STP. This can be obtained as follow:

1 mole of oxygen (O2) occupies 22.4 L at STP.

Therefore, Xmol of oxygen will occupy 585 L tank at STP i.e

Xmol of oxygen = 585/22.4

Xmol of oxygen = 26.12 moles

Next, we shall determine the mass of 26.12 moles of oxygen. This can be obtained as follow:

Mole of O2 = 26.12 moles

Molar mass of O2 = 2 × 16 = 32 g/mol

Mass of O2 =?

Mole = mass /Molar mass

26.12 = mass of O2 /32

Cross multiply

Mass of O2 = 26.12 × 32

Mass of O2 = 835.84 g

Finally, we shall convert 835.84 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

835.84 g = 835.84 g × 1 Kg / 1000 g

835.84 g = 0.835 Kg

Thus, 835.84 g is equivalent to 0.835 Kg.

Therefore, the mass of oxygen needed to fill the 585 L tank at STP is 0.835 Kg

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.