How many tons of asphalt concrete will be required to overlay a 2.5 mile long 24 ft wide road with 3in of wearing course asphalt concrete that has a density of f 147.9PCF?

To determine the weight of the asphalt needed, first determine the area of the surface to be paved.

Since the shape of the road is a rectangle, use the formula of area of rectangle.

A = Length xx Width

Before plugging-in the values, convert the 2.5 miles to feet in order that the dimension to have same unit.

So,

2.5 mi xx (5280 ft)/(1mi) = 13200ft

Now that the length is in feet, plug-in the values of dimension of the road to the formula of area of rectangle.

A=13200*24

A=316800

Hence, the area to be paved is 316 800 ft^2 .

Next, determine the volume. Use the formula:

V = Area xx thickness

Before substituting the values, convert the thickness to feet in order to have same units.

So,

3 i n xx (1ft)/(12 i n)=0.25ft

Then, substitute the values of the area and thickness to the formula of volume.

V=316800*0.25=79200

Thus, the volume of the asphalt needed is 79200 ft^3.

Next, to determine its weight , multiply that with the given density 1479 pounds per cubic feet (1479 lb/ft^3).

W=79200*1479=117136800

So, the weight is 11 7136 800 lbs.

Then, convert it to tons.

117136800 lbs xx (1t o n)/(2000lbs) = 58568.4 t o n s

Explanation:i did the math

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.