Approximately what mass of CuSO4*5H20 (250 g mol^-1) is required to prepare 250 mL of 0.10 M copper(ll) sulfate solution?
A) 4.0 g
B
6.2 g
С
34 g
D
85 g
E
140 g

Mass of CuSO₄.5H₂0 = 6.25 g (B)

MW CuSO₄.5H₂0 =250 g/ mol

mol of CuSO₄

mass of CuSO₄ (MW=159.61 g/mol)

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied